8 in Binary

8 in binary is 1000. To find decimal to binary equivalent, divide 8 successively by 2 until the quotient becomes 0. The binary equivalent can be obtained by writing the remainder in each division step from the bottom to the top.

We know that 8 in binary is 1000 and 7 is 111. Using the binary multiplication rules (0 × 0 = 0; 0 × 1 = 0 ; 1 × 0 = 0 and 1 × 1 = 1), we can multiply 1000 × 111 = 111000 which is 56 in the decimal number system. [8 × 7 = 56]

We can divide 8 by 2 and continue the division till we get 0. Note down the remainder in each step.

Write the remainders from MSB to LSB. Therefore, the decimal number 8 in binary can be represented as 1000.

We can count the number of zeros and ones to see how many bits are used to represent 8 in binary i.e. 1000. Therefore, we have used 4 bits to represent 8 in binary.

8 in binary number system is 1000 and 53 is 110101. We can add the binary equivalent of 8 and 53 using binary addition rules [0 + 0 = 0, 0 + 1 = 1, 1 + 1 = 10 note that 1 is a carry over to the next bit]. Therefore, (1000)₂ + (110101)₂ = (111101)₂ which is nothing but 61.